44 lines
1.5 KiB
SQL
44 lines
1.5 KiB
SQL
{% set ok_status = "Approved" %}
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with
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int_athena__verifications as (select * from {{ ref("int_athena__verifications") }}),
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stg_seed__athena_price_history as (
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select * from {{ ref("stg_seed__athena_price_history") }}
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),
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-- CTE to rank verifications by updated_at_utc per id_booking
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ranked_verifications as (
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select
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v.*,
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row_number() over (
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partition by v.id_booking order by v.updated_at_utc asc
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) as rn
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from int_athena__verifications v
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where v.version = 'V1' and v.id_booking is not null
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)
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select
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1 as lol,
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2 as lolol,
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v.id_verification,
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v.id_booking,
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v.verification_status,
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v.is_cancelled,
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-- Charge for 1 night if number_nights = 0
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case
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when v.number_nights = 0 and v.verification_status = '{{ ok_status }}'
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then ph.fee_per_night_gbp
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when v.verification_status = '{{ ok_status }}'
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then v.number_nights * ph.fee_per_night_gbp
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else 0
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end as ok_status_fee_in_gbp,
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v.created_date_utc,
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v.checkout_date_utc
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from ranked_verifications v
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left join
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stg_seed__athena_price_history ph
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-- The following condition ensures avoiding duplicates.
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-- Keep in mind that the start_at_utc is inclusive to the price,
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-- while the end_at_utc is exclusive.
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on v.checkout_at_utc >= ph.start_at_utc
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and v.checkout_at_utc < ph.end_at_utc
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where
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-- Select only the most recent verification for each id_booking
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v.rn = 1
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