a3b1decb08
As today it's 1st of July, the logic of selecting all days of the current month for MTD purposes on the business KPIs is ko, since we select up to yesterday. This PR allows to consider the last day of the previous month as 'current month' only for the first day of the following month, thus ensuring that the most up-to-date data is always displayed in the MTD tab. Related work items: #17745
60 lines
2.3 KiB
SQL
60 lines
2.3 KiB
SQL
/*
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This model provides Month-To-Date (MTD) necessary dates for MTD-based models to work.
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- For month-to-month complete information, it retrieves all end month dates that have elapsed since 2020.
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- For month-to-date information, it retrieves the days of the current month of this year up to yesterday.
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Additionally, it also gets the days of its equivalent month from last year previous the current day of month of today.
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Example:
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Imagine we have are at 4th June 2024.
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- We will get the dates for 1st, 2nd, 3rd of June 2024.
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- We will also get the dates for 1st, 2nd, 3rd of June 2023.
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- We will get all end of months from 2020 to yesterday,
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i.e., 31st January 2020, 29th February 2020, ..., 30th April 2024, 31st May 2024.
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*/
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with
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int_dates as (select * from {{ ref("int_dates") }} where date_day >= {{ var("start_date") }}),
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raw_dates as (
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select
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id.year_number as year,
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id.month_of_year as month,
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id.day_of_month as day,
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id.date_day as date,
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id.month_start_date as first_day_month,
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id.month_end_date as last_day_month,
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now()::date as today
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from int_dates id
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)
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-- Dates keeps only end of month (EOM) dates, as well as
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-- dates corresponding to the current month and the same month last year
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select distinct
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rd.year,
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rd.month,
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rd.day,
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rd.date,
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rd.first_day_month,
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rd.last_day_month,
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case when rd.date = rd.last_day_month then 1 else 0 end as is_end_of_month,
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case
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when date_trunc('month', rd.date) = date_trunc('month', rd.today) then 1
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-- If today is 1st of Month, include last day of month for MTD display
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when rd.today = rd.last_day_month + 1 then 1
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else 0
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end as is_current_month
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from raw_dates rd
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where
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rd.today > rd.date
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-- include only up-to yesterday
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and (
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rd.date = rd.last_day_month
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-- keep all last day of the month
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or rd.date >= date_trunc('month', rd.today)
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-- keep all individual days of the current month
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or (
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rd.year = extract(year from rd.today) - 1
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and rd.month = extract(month from rd.today)
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and rd.day < extract(day from rd.today)
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)
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-- keep all days of same month last day up to yesterday's day
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)
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